3b^2+7b-2=0

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Solution for 3b^2+7b-2=0 equation: 



3b^2+7b-2=0

a = 3; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·3·(-2)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{73}}{2*3}=\frac{-7-\sqrt{73}}{6}
$


$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{73}}{2*3}=\frac{-7+\sqrt{73}}{6}
$

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